Integrand size = 13, antiderivative size = 70 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=-\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}} \]
[Out]
Time = 0.01 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {43, 65, 211} \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\frac {3 \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}-\frac {x^{3/2}}{2 b (a+b x)^2} \]
[In]
[Out]
Rule 43
Rule 65
Rule 211
Rubi steps \begin{align*} \text {integral}& = -\frac {x^{3/2}}{2 b (a+b x)^2}+\frac {3 \int \frac {\sqrt {x}}{(a+b x)^2} \, dx}{4 b} \\ & = -\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \int \frac {1}{\sqrt {x} (a+b x)} \, dx}{8 b^2} \\ & = -\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \text {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,\sqrt {x}\right )}{4 b^2} \\ & = -\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.84 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=-\frac {\sqrt {x} (3 a+5 b x)}{4 b^2 (a+b x)^2}+\frac {3 \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}} \]
[In]
[Out]
Time = 0.07 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.71
method | result | size |
derivativedivides | \(\frac {-\frac {5 x^{\frac {3}{2}}}{4 b}-\frac {3 a \sqrt {x}}{4 b^{2}}}{\left (b x +a \right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2} \sqrt {a b}}\) | \(50\) |
default | \(\frac {-\frac {5 x^{\frac {3}{2}}}{4 b}-\frac {3 a \sqrt {x}}{4 b^{2}}}{\left (b x +a \right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2} \sqrt {a b}}\) | \(50\) |
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 185, normalized size of antiderivative = 2.64 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\left [-\frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \sqrt {-a b} \log \left (\frac {b x - a - 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) + 2 \, {\left (5 \, a b^{2} x + 3 \, a^{2} b\right )} \sqrt {x}}{8 \, {\left (a b^{5} x^{2} + 2 \, a^{2} b^{4} x + a^{3} b^{3}\right )}}, -\frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (5 \, a b^{2} x + 3 \, a^{2} b\right )} \sqrt {x}}{4 \, {\left (a b^{5} x^{2} + 2 \, a^{2} b^{4} x + a^{3} b^{3}\right )}}\right ] \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 605 vs. \(2 (61) = 122\).
Time = 16.62 (sec) , antiderivative size = 605, normalized size of antiderivative = 8.64 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\begin {cases} \frac {\tilde {\infty }}{\sqrt {x}} & \text {for}\: a = 0 \wedge b = 0 \\\frac {2 x^{\frac {5}{2}}}{5 a^{3}} & \text {for}\: b = 0 \\- \frac {2}{b^{3} \sqrt {x}} & \text {for}\: a = 0 \\\frac {3 a^{2} \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {3 a^{2} \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {6 a b \sqrt {x} \sqrt {- \frac {a}{b}}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} + \frac {6 a b x \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {6 a b x \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {10 b^{2} x^{\frac {3}{2}} \sqrt {- \frac {a}{b}}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} + \frac {3 b^{2} x^{2} \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {3 b^{2} x^{2} \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} & \text {otherwise} \end {cases} \]
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.87 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=-\frac {5 \, b x^{\frac {3}{2}} + 3 \, a \sqrt {x}}{4 \, {\left (b^{4} x^{2} + 2 \, a b^{3} x + a^{2} b^{2}\right )}} + \frac {3 \, \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} b^{2}} \]
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.67 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\frac {3 \, \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} b^{2}} - \frac {5 \, b x^{\frac {3}{2}} + 3 \, a \sqrt {x}}{4 \, {\left (b x + a\right )}^{2} b^{2}} \]
[In]
[Out]
Time = 0.15 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.83 \[ \int \frac {x^{3/2}}{(a+b x)^3} \, dx=\frac {3\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x}}{\sqrt {a}}\right )}{4\,\sqrt {a}\,b^{5/2}}-\frac {\frac {5\,x^{3/2}}{4\,b}+\frac {3\,a\,\sqrt {x}}{4\,b^2}}{a^2+2\,a\,b\,x+b^2\,x^2} \]
[In]
[Out]